In a family from the Middle East with a history of congenital deafness and muteness due to GJB2 gene mutation, which is an autosomal recessive condition, the population incidence is 4/10000. The frequency of carriers in this population is

A0.01
B0.02
C0.04
D0.0002

Correct answer: B. 0.02

The frequency of carriers can be calculated using the formula: q = √(p), where p is the incidence rate (4/10000 or 0.0004). Therefore, q = √(0.0004) = 0.02.

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